(x-3)(x^2+1)=0

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Solution for (x-3)(x^2+1)=0 equation: 


Simplifying
(x + -3)(x2 + 1) = 0

Reorder the terms:
(-3 + x)(x2 + 1) = 0

Reorder the terms:
(-3 + x)(1 + x2) = 0

Multiply (-3 + x) * (1 + x2)
(-3(1 + x2) + x(1 + x2)) = 0
((1 * -3 + x2 * -3) + x(1 + x2)) = 0
((-3 + -3x2) + x(1 + x2)) = 0
(-3 + -3x2 + (1 * x + x2 * x)) = 0
(-3 + -3x2 + (1x + x3)) = 0

Reorder the terms:
(-3 + 1x + -3x2 + x3) = 0
(-3 + 1x + -3x2 + x3) = 0

Solving
-3 + 1x + -3x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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